My submissions to SPOJ problem- TEST

My interest lies in programming languages. Actually, I have a bad habit of trying every type of weird thing and this time I came up with the idea of trying a simple problem in every possible programming language I know. I tried to solve the first problem of SPOJ named Test. Here are my codes:

C:

#include < stdio.h >

int main()
{
int n;
scanf("%d",&n);
while (n!= 42) {
printf(""%d", n);
scanf("%d",&n);
}
return 0;
}

C++:

#include < iostream >
using namespace std;

int main()
{
int n;
cin>>n;
while (n!= 42) {
cout<>n;
}
return 0;
}

C#:

using System;
public class Test
{
public static void Main()
{
int n;
while ((n = int.Parse(Console.ReadLine()))!=42)
Console.WriteLine(n);
}
}

Java:

public class Main
{
public static void main (String[] args) throws java.lang.Exception
{
java.io.BufferedReader r = new java.io.BufferedReader (new java.io.InputStreamReader (System.in));
String s;
while (!(s=r.readLine()).startsWith("42"))
System.out.println(s);
}
}

Python:

n = input()
  while n != 42:
  print n
  n = input()

PHP:

< ? php while(1) { fscanf(STDIN,"%d",$n); if ($n == 42) break; print "$n\n"; } ? >


BrainF*ck:

>+[>>,----------[>,----------]+++++[<-------->-]<[>>-<]>+[
-<+++++++[<------>-]<[>>-<]>+[
-<<[>>-<]>+[<<->>->]>
]<+++++++[<++++++>-]>>
]<++++++++[<+++++>-]< [<]<[>>[++++++++++.>]++++++++++.[[-]<]]<]

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Some more problems of SPOJ...

I recently breached into the top 1200 ranks in the world, but sad news is, soon I'll be thrown out too. The points keep on decreasing on a regular basis. Never mind this works as an incentive to work on more and more problems. :)
So, m writing this post for some more problems of SPOJ. The problems I m going to discuss are of an average level.

BISHOPS: Its an easy problem, if we try verbally. The answer is (2*n-2) i.e. equal to the number of diagonals. But the difficulty lies in the range of the inputs. N<=10^100..!! OMG!!.. :).. Try strings..

MINCOUNT: Actually what I did.. I tried it out for certain test cases and found that the answer is.. (n*(n+1)/2)/3.. i.e. the total number of coins in the triangle divided by 3. But why its so.. its still unanswered for me.. kindly post the explanation if you get one..!! :)

HUBULLU: Same mincount type problem here too.. seeing the discussion in the forum I got some hints that who so ever plays first wins.. So, it became a very very easy question for me to crack but why it happens is yet not understood by me..

TRICOUNT: Its another mathematics problem.. try it for sometime with all yours geometrical anlysis and at one time you will definitely come out with a solution that is much like (t*(t+2)*(2*t+1))/8.. where t is the level of triangle. Try it now yourself..!!

SAMER08F: Another age old problem of how many squares are there in a given bunch of squares?? Answer lies in the sum all squared numbers till the number of squares in each side of the grid i.e. if N=8 then answer= (1*1) + (2*2) + ... + (8*8).

Seeing my last three posts of SPOJ I think now its easy for any newbie to get started. So, no more discussing algorithms of SPOJ problems from my side. Keep practicing and who knows one day you beat [Trichromatic] XilinX..!! :p

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SPOJ: Some very easy problems

Its been a month since I have started coding in SPOJ. There are over 5000 problems present there. Its really gets very tough when one tries to get some easy problems from that lot. So, I dedicate this post to beginners. Go for the below mentioned problems.

Some very easy classical problems:

TEST- This is the first problem I solved in SPOJ. I recommend the same for you. It gives a brief introduction of the whole environment. What you need to do is to accept and print the input by the user until you come across 42. The easiest problem at SPOJ and a confidence booster to begin with..!! ;)

ADDREV- Take two numbers as input. Reverse both. Add the reversed number. Reverse again. Simple..!! The thing you need to keep in mind is that you have to provide the number of test cases first. While taking the inputs you can print the result too. You need not store them and print later.

FASHION- Quite big explanation of the problem (a bit interesting too ;) ). The only thing you need to keep in mind is that you have to sort the degree of hotness of men and women and then multiply and add them up. If you do not sort them, it will give a WA.

MIRRORED- Print "Mirrored pair" wherever you confront "bd" or "db" or "pq" or "qp", otherwise print "Ordinary pair". Don't forget to print "Ready" in the beginning. You do not have to take the test cases as input here. Just end the input when you confront two spaces. I got an AC at very first attempt..!! Hope the same for you.. :)

NSTEPS- Analize the graph properly. Whenever x and y co-ordinates are even the corresponding output is (x+y) for input (x=y) and (x=y-2). When they are odd the corresponding ouput is (x+y-1) for input (x=y) and (y=x-2). You can also do the problem with a different approach too. You can form a series for the numbers, and hence, generate the output.

OFORTUNE- Common.. don't get astonished by the enormous length of the question. Try tackling the problem. It just needs six inputs and a simple interest and compound interest formula implementation thats it.. Try it.. You will gain a hell lot of points..!!

Some very easy challenge problems:

SIZECON- The difficulty doesn't lie in the problem statement. The difficulty lies in the choice of programming language. I managed to do it in 96 characters. Best solution in c++ has 70 characters in it. Perl language wins with just 6 characters..!!

BFWRITE- I have already written a post about this problem. Try learning Brainf_ck language and solve this problem too. Here's the link to my post.

More easy problems are being searched. Kindly mention some in comments if you confront one.. Here's my SPOJ handle.. vaibhav_pandey.

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Getting started with SPOJ (Sphere Online Judge)

After successfully getting involved in SPOJ I think I must give a little idea of it to others too. SPOJ is an online coding website for practicing ACM-ICPC style problems.
You need to join this website if you are interested in coding and have a thirst to solve new problems otherwise you can sit back and relax hearing your music stuff.. :p

To start with you can register for SPOJ here.
After getting registered you can see number of problems. Right now there are around 4K+ problems at SPOJ. For submitting a problem in whichever language you desire you can click submit and submit your file or directly the source code. One of the best things about online judges is their instant feedback. You dont have to wait for your program to get judged! The judge results are:

• Accepted – The output from your program perfectly matched the required output. This problem is then added to your list of accepted problems.
• Time Limit Exceeded – It means your program took too long to execute. Try optimizing your program and check for accidental infinite loops.
• Wrong Answer – Your program ran on time, but it did not produce the required output.
• Compile Error -Your program had some syntax error. For these errors, click on the text “Compile Error” in the judge result. It`ll take you a page which will list the compile errors and their line numbers in your program. The compilation error can also be sent to you as mail.
• Runtime Error – This is usually accompanied by a code like SIGSEV. It can happen due to a lot of reasons, but the two most common are using too much memory ( you can use around 6000*6000*4 bytes of memory ) and not remembering to use int main() and return 0 in your programs. (NZEC error).

Your ranking in SPOJ arena is dynamic. More the number of users who solve the problem you'v solved lesser will be points gained. The points you gain in SPOJ come with the formula:

points= 80/(40+users successfully solved the problem)

So, more the difficult question you solve more points you get and higher is your rank. Even your institute gets ranked on your points. Check your institute's rank here.

Here is my SPOJ handle.. vaibhav_pandey

Start coding now!!!

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